Question Number 50175 by Tinkutara last updated on 14/Dec/18
Answered by ajfour last updated on 14/Dec/18
$${centroid}\:\:\:\:\:{x}_{{G}} \:=\:\frac{\Sigma{x}_{\mathrm{1}} }{\mathrm{3}}\:. \\ $$$${circumcenter}\:\:\left({i}\:{hope},\:{can}\:{qualify}\:{too}\right). \\ $$
Commented by Tinkutara last updated on 15/Dec/18
Sir why not orthocenter also?