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Question-50717




Question Number 50717 by Tawa1 last updated on 19/Dec/18
Answered by tanmay.chaudhury50@gmail.com last updated on 19/Dec/18
x+(√y) −(√x) −y=4  ((√x)+(√y) )((√x) −(√y) )−((√x) −(√y) )=4  ((√x) −(√y) )((√x) +(√y) −1)=4   by logic trial x=9  y= 4  so   z=1
x+yxy=4(x+y)(xy)(xy)=4(xy)(x+y1)=4bylogictrialx=9y=4soz=1
Commented by Tawa1 last updated on 19/Dec/18
God bless you sir
Godblessyousir
Answered by ajfour last updated on 19/Dec/18
let   x+y+z = s  ⇒  (√x)−x = 8−s          (√y)−y = 12−s          (√z)−z = 14−s      x−(√x)+(8−s)=0      (√x) = (1/2)+((√(1+4(s−8)))/2)    (+ve root )     x = (√x)+s−8         = ((√(1+4(s−8)))/2)+(1/2)+s−8   ...(i)     s = x+y+z  ⇒  2s = (√(1+4(s−8)))+1+2(s−8)                    +(√(1+4(s−12)))+1+2(s−12)                     +(√(1+4(s−14)))+1+2(s−14)  ⇒ (√(4s−31))+(√(4s−47))+(√(4s−55))+4s = 65  ⇒  s = 14  And from  (i)  ⇒  x = ((√(1+4(s−8)))/2)+(1/2)+s−8  ⇒   x = 9, y = 4 , z = 1 .
letx+y+z=sxx=8syy=12szz=14sxx+(8s)=0x=12+1+4(s8)2(+veroot)x=x+s8=1+4(s8)2+12+s8(i)s=x+y+z2s=1+4(s8)+1+2(s8)+1+4(s12)+1+2(s12)+1+4(s14)+1+2(s14)4s31+4s47+4s55+4s=65s=14Andfrom(i)x=1+4(s8)2+12+s8x=9,y=4,z=1.
Commented by Tawa1 last updated on 19/Dec/18
God bless you sir
Godblessyousir

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