Question Number 50936 by Rio Michael last updated on 22/Dec/18
Commented by Rio Michael last updated on 22/Dec/18
$${the}\:{figure}\:{above}\:{is}\:{a}\:{solid}\:{with}\:{trapezium}\:{PQRS}\:{as}\:{its}\:{uniform} \\ $$$${cross}−{section}. \\ $$$$\left.{a}\right)\:{Find}\:{the}\:{area}\:{of}\:{the}\:{trapezuim}\:{PQRS} \\ $$$$\left.{b}\right)\:{calculate}\:{the}\:{volume}\:{of}\:{the}\:{solid}\:{figure}. \\ $$
Answered by hassentimol last updated on 22/Dec/18
$$\mathrm{A}_{\mathrm{Trapezium}\:} =\:\frac{\mathrm{height}\:×\:\left(\mathrm{big}\:\mathrm{side}\:+\:\mathrm{small}\:\mathrm{side}\right)}{\mathrm{2}} \\ $$$$\mathrm{A}_{\mathrm{Trapezium}} \:=\:\frac{\mathrm{12}\:×\:\left(\mathrm{11}\:+\:\mathrm{6}\right)}{\mathrm{2}}\:=\:\mathrm{102}\:\mathrm{m}^{\mathrm{2}} \\ $$$$ \\ $$$${and} \\ $$$$ \\ $$$$\mathrm{Vol}\:=\:\mathrm{A}_{\mathrm{Trapezium}} \:×\:\mathrm{Height} \\ $$$$\mathrm{Vol}\:=\:\mathrm{102}\:×\:\mathrm{8}\:=\:\mathrm{816}\:\mathrm{m}^{\mathrm{3}} \\ $$