Question Number 50952 by ajfour last updated on 22/Dec/18
Commented by ajfour last updated on 22/Dec/18
$${Find}\:{maximum}\:{area}\:{between}\:{the} \\ $$$${parabola}\:{and}\:{its}\:{chord}\:{of}\:{length}\:{l}. \\ $$
Commented by mr W last updated on 22/Dec/18
$${i}\:{guess}\:{due}\:{to}\:{symmetry}: \\ $$$${A}_{{max}} =\frac{\mathrm{2}}{\mathrm{3}}×{l}×\left(\frac{{Al}^{\mathrm{2}} }{\mathrm{4}}\right)=\frac{{Al}^{\mathrm{3}} }{\mathrm{6}} \\ $$
Commented by ajfour last updated on 23/Dec/18
