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Question-51220




Question Number 51220 by Gulay last updated on 25/Dec/18
Commented by Gulay last updated on 25/Dec/18
sir help me pls
sirhelpmepls
Answered by afachri last updated on 25/Dec/18
55 = x  52 = y  (x − y )^3  = x^2 − 3x^2 y + 3xy^2 − y^3   (55−52)^3 = 55^3 − 3(55^2 )(52) + 3(55)(52^2 )− 52^3   the product in RHS with evaluate LHS.  (55 − 52)^3 = 3^3                              = 27
55=x52=y(xy)3=x23x2y+3xy2y3(5552)3=5533(552)(52)+3(55)(522)523theproductinRHSwithevaluateLHS.(5552)3=33=27
Commented by Gulay last updated on 25/Dec/18
thank you so much sir
thankyousomuchsir
Commented by afachri last updated on 25/Dec/18
ur welcome, Sir
urwelcome,Sir

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