Question Number 51228 by Gulay last updated on 25/Dec/18
Commented by Gulay last updated on 25/Dec/18
$$\mathrm{y}=\mathrm{2}.\mathrm{3} \\ $$$$\mathrm{sir}\:\mathrm{could}\:\mathrm{you}\:\mathrm{help}\:\mathrm{me} \\ $$
Answered by $@ty@m last updated on 25/Dec/18
$${Use}\:{a}^{\mathrm{2}} −{b}^{\mathrm{2}} =\left({a}+{b}\right)\left({a}−{b}\right) \\ $$$$\therefore\:{the}\:{given}\:{expression} \\ $$$$=\mathrm{6}{y} \\ $$$$=\mathrm{6}×\mathrm{2}.\mathrm{3}\:\left({given}\:{y}=\mathrm{2}.\mathrm{3}\right) \\ $$$$=\mathrm{13}.\mathrm{8} \\ $$
Commented by Gulay last updated on 25/Dec/18
$$\mathrm{thank}\:\mathrm{you}\:\mathrm{so}\:\mathrm{much}\:\mathrm{sir} \\ $$$$\mathrm{You}'\mathrm{re}\:\mathrm{perfect} \\ $$$$ \\ $$$$ \\ $$