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Question-51279




Question Number 51279 by ajfour last updated on 25/Dec/18
Commented by ajfour last updated on 25/Dec/18
If both ellipses have the same  parameters a and b, find h.
$${If}\:{both}\:{ellipses}\:{have}\:{the}\:{same} \\ $$$${parameters}\:{a}\:{and}\:{b},\:{find}\:\boldsymbol{{h}}. \\ $$
Answered by mr W last updated on 25/Dec/18
(x^2 /a^2 )+(y^2 /b^2 )=1  P((h/2),(b/2))  (h^2 /(4a^2 ))+(b^2 /(4b^2 ))=1  (h^2 /a^2 )=3  ⇒h=(√3)a
$$\frac{{x}^{\mathrm{2}} }{{a}^{\mathrm{2}} }+\frac{{y}^{\mathrm{2}} }{{b}^{\mathrm{2}} }=\mathrm{1} \\ $$$${P}\left(\frac{{h}}{\mathrm{2}},\frac{{b}}{\mathrm{2}}\right) \\ $$$$\frac{{h}^{\mathrm{2}} }{\mathrm{4}{a}^{\mathrm{2}} }+\frac{{b}^{\mathrm{2}} }{\mathrm{4}{b}^{\mathrm{2}} }=\mathrm{1} \\ $$$$\frac{{h}^{\mathrm{2}} }{{a}^{\mathrm{2}} }=\mathrm{3} \\ $$$$\Rightarrow{h}=\sqrt{\mathrm{3}}{a} \\ $$
Commented by ajfour last updated on 25/Dec/18
you saw it straight Sir, one might   get lost! Thanks.
$${you}\:{saw}\:{it}\:{straight}\:{Sir},\:{one}\:{might}\: \\ $$$${get}\:{lost}!\:{Thanks}. \\ $$

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