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Question-51465




Question Number 51465 by mr W last updated on 27/Dec/18
Commented by Rasheed.Sindhi last updated on 27/Dec/18
Sir 4-digit numbers I think?
Sir4digitnumbersIthink?
Commented by mr W last updated on 27/Dec/18
Yes, 4−digits numbers only.
Yes,4digitsnumbersonly.
Commented by Rasheed.Sindhi last updated on 27/Dec/18
711040?
711040?
Commented by mr W last updated on 27/Dec/18
correct! thank you sir!
correct!thankyousir!
Answered by tanmay.chaudhury50@gmail.com last updated on 27/Dec/18
total four digit numbers formed=4×4×4×4=256  during addition  we have to add each digit 64 times.  1)so unit place of the sum of all four digit is  [64×(1+2+3+4)=640]→0  2)when we add all digit of second place +carry  forward 64 [640+64=704] so tenth digit of sum→4  3)hundred place [640+70=710]→0  4)thousand place [640+71=711]→1  so answer is 711040
totalfourdigitnumbersformed=4×4×4×4=256duringadditionwehavetoaddeachdigit64times.1)sounitplaceofthesumofallfourdigitis[64×(1+2+3+4)=640]02)whenweaddalldigitofsecondplace+carryforward64[640+64=704]sotenthdigitofsum43)hundredplace[640+70=710]04)thousandplace[640+71=711]1soansweris711040
Commented by mr W last updated on 27/Dec/18
answer is correct sir∙ thank you!
answeriscorrectsirthankyou!
Answered by mr W last updated on 27/Dec/18
sum of all possible numbers is equal  to the sum of all values which their  digits represent:  (4^4 /4)×(1000+100+10+1)×(1+2+3+4)  =(4^4 /4)×1111×10=711040
sumofallpossiblenumbersisequaltothesumofallvalueswhichtheirdigitsrepresent:444×(1000+100+10+1)×(1+2+3+4)=444×1111×10=711040
Commented by tanmay.chaudhury50@gmail.com last updated on 27/Dec/18
unique method...excellent...
uniquemethodexcellent
Commented by ajfour last updated on 27/Dec/18
standard old method..
standardoldmethod..

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