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Question-52108




Question Number 52108 by ajfour last updated on 03/Jan/19
Answered by mr W last updated on 03/Jan/19
Area=((cR)/2)=((√((a+b+c)(−a+b+c)(a−b+c)(a+b−c)))/4)  ⇒R=((√((a+b+c)(−a+b+c)(a−b+c)(a+b−c)))/(2c))
$${Area}=\frac{{cR}}{\mathrm{2}}=\frac{\sqrt{\left({a}+{b}+{c}\right)\left(−{a}+{b}+{c}\right)\left({a}−{b}+{c}\right)\left({a}+{b}−{c}\right)}}{\mathrm{4}} \\ $$$$\Rightarrow{R}=\frac{\sqrt{\left({a}+{b}+{c}\right)\left(−{a}+{b}+{c}\right)\left({a}−{b}+{c}\right)\left({a}+{b}−{c}\right)}}{\mathrm{2}{c}} \\ $$
Commented by ajfour last updated on 03/Jan/19
Oh Yes Sir. i should have seen.
$${Oh}\:{Yes}\:{Sir}.\:{i}\:{should}\:{have}\:{seen}. \\ $$

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