Question Number 52490 by Gulay last updated on 08/Jan/19
Commented by Gulay last updated on 08/Jan/19
$$\mathrm{sir}\:\mathrm{could}\:\mathrm{you}\:\mathrm{he}\:\mathrm{me}? \\ $$
Answered by $@ty@m last updated on 08/Jan/19
Answered by malwaan last updated on 09/Jan/19
$$\mathrm{x}=\frac{\mathrm{9}−\left(−\mathrm{6}\right)}{\mathrm{1}−\mathrm{6}}=\frac{\mathrm{15}}{−\mathrm{5}}=−\mathrm{3} \\ $$$$\mathrm{y}=\frac{−\mathrm{3}−\mathrm{27}}{\mathrm{1}−\mathrm{6}}=\frac{−\mathrm{30}}{−\mathrm{5}}=\mathrm{6} \\ $$$$\Rightarrow\left\{\left(\mathrm{x};\mathrm{y}\right)\right\}=\left\{\left(−\mathrm{3};\mathrm{6}\right)\right\} \\ $$
Commented by Gulay last updated on 09/Jan/19
$$\mathrm{thank}\:\mathrm{you}\:\mathrm{so}\:\mathrm{much}\:\mathrm{sir} \\ $$
Commented by malwaan last updated on 10/Jan/19
you are welcome