Question-52593

Question Number 52593 by Tinkutara last updated on 10/Jan/19

Commented by Tinkutara last updated on 10/Jan/19

b part please

Answered by ajfour last updated on 11/Jan/19

(μ_{2} - μ_{1}) t = d \sin θ_{0}

\frac{y_{0}}{D} = \tan θ_{0} \approx \sin θ_{0} = \frac{(μ_{2} - μ_{1}) t}{d}

t h i s g i v e s y_{0} \approx 1.25 c m

y_{1} = y_{0} + \frac{λ D}{d} = 1.25 c m \pm 0.49 m m

i w a s w r o n g, a n d i a m s t i l l w r o n g,

i s h a l l t r y a g a i n . .

Commented by Tinkutara last updated on 11/Jan/19

But answers given are (a) 4.9×10^-4 m (b) 0.021 cm on one side and 0.028 cm on other side

Commented by Tinkutara last updated on 11/Jan/19

But Sir I also got the same answers as yours, then where is the mistake?