Question Number 52847 by peter frank last updated on 14/Jan/19
Commented by peter frank last updated on 14/Jan/19
Commented by peter frank last updated on 14/Jan/19
$${Q}_{\mathrm{1}} =\frac{\pi{p}_{\mathrm{1}} {r}_{\mathrm{1}} ^{\mathrm{4}} }{\mathrm{8}\eta{l}_{\mathrm{1}} }……\left({i}\right) \\ $$$${Q}_{\mathrm{2}} =\frac{\pi{p}_{\mathrm{2}} {r}_{\mathrm{2}} ^{\mathrm{4}} }{\mathrm{8}\eta{l}_{\mathrm{2}} }…….\left({ii}\right) \\ $$$${let}\:{x}\:{be}\:{pressure}\:{at}\:{junction} \\ $$$${Q}_{\mathrm{1}\:\:} ={Q}_{\mathrm{2}} \\ $$$$ \\ $$