Question Number 52992 by prakash jain last updated on 16/Jan/19
![](https://www.tinkutara.com/question/6950.png)
Commented by prakash jain last updated on 16/Jan/19
![Correct answer is ((4−R)/(2R)), NTA has given ((4+R)/(2R)). This question is also from 9th Jan morning JEE main exam.](https://www.tinkutara.com/question/Q52995.png)
Answered by tanmay.chaudhury50@gmail.com last updated on 16/Jan/19
![P_A =N_A (((RT)/V)) P_B =N_B (((RT)/V)) P=P_A +P_B =((RT)/V)(N_A +N_B ) N_A +N_B =((PV)/(RT)) N_B =((PV)/(RT))−N_A N_B =((200×10)/(R×1000))−0.5 N_B =(2/R)−(1/2) N_B =((4−R)/(2R))](https://www.tinkutara.com/question/Q53000.png)
Answered by afachri last updated on 16/Jan/19
![](https://www.tinkutara.com/question/6952.png)
Answered by FelipeLz last updated on 26/Oct/21
![PV = nRT 2.10^2 ∙10 = ((1/2)+x)∙R∙10^3 2 = ((1/2)+x)∙R 2 = ((1/2)+x)∙R (2/R) = (1/2)+x x = (2/R)−(1/2) x = ((4−R)/(2R))](https://www.tinkutara.com/question/Q157654.png)