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Question-53340




Question Number 53340 by aseerimad last updated on 20/Jan/19
Answered by tanmay.chaudhury50@gmail.com last updated on 20/Jan/19
a=18^o     method 1  ((sin54)/(cos54))−((sin36)/(cos36))  ((sin54cos36−cos54sin36)/(cos54cos36))  ((sin(54−36))/(cos54cos36))  =((2sin18)/(2cos54cos36))  =((2sin18)/(cos90+cos18))  =2tan18  method 2  put the value of sin18 ,cos18 and sin36 and  cos 36 etc...
$${a}=\mathrm{18}^{{o}} \\ $$$$ \\ $$$${method}\:\mathrm{1} \\ $$$$\frac{{sin}\mathrm{54}}{{cos}\mathrm{54}}−\frac{{sin}\mathrm{36}}{{cos}\mathrm{36}} \\ $$$$\frac{{sin}\mathrm{54}{cos}\mathrm{36}−{cos}\mathrm{54}{sin}\mathrm{36}}{{cos}\mathrm{54}{cos}\mathrm{36}} \\ $$$$\frac{{sin}\left(\mathrm{54}−\mathrm{36}\right)}{{cos}\mathrm{54}{cos}\mathrm{36}} \\ $$$$=\frac{\mathrm{2}{sin}\mathrm{18}}{\mathrm{2}{cos}\mathrm{54}{cos}\mathrm{36}} \\ $$$$=\frac{\mathrm{2}{sin}\mathrm{18}}{{cos}\mathrm{90}+{cos}\mathrm{18}} \\ $$$$=\mathrm{2}{tan}\mathrm{18} \\ $$$${method}\:\mathrm{2} \\ $$$${put}\:{the}\:{value}\:{of}\:{sin}\mathrm{18}\:,{cos}\mathrm{18}\:{and}\:{sin}\mathrm{36}\:{and} \\ $$$${cos}\:\mathrm{36}\:{etc}… \\ $$

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