Question-53340

Question Number 53340 by aseerimad last updated on 20/Jan/19

Answered by tanmay.chaudhury50@gmail.com last updated on 20/Jan/19

a = 18^{o}

m e t h o d 1

\frac{s i n 54}{c o s 54} - \frac{s i n 36}{c o s 36}

\frac{s i n 54 c o s 36 - c o s 54 s i n 36}{c o s 54 c o s 36}

\frac{s i n (54 - 36)}{c o s 54 c o s 36}

= \frac{2 s i n 18}{2 c o s 54 c o s 36}

= \frac{2 s i n 18}{c o s 90 + c o s 18}

= 2 t a n 18

m e t h o d 2

p u t t h e v a l u e o f s i n 18, c o s 18 a n d s i n 36 a n d

c o s 36 e t c \dots