Question-53550

Question Number 53550 by vajpaithegrate@gmail.com last updated on 23/Jan/19

Commented by Kunal12588 last updated on 23/Jan/19

Commented by Kunal12588 last updated on 23/Jan/19

t h e y a r e n o t i n t e r s e c t i n g a n s w e r s h o u l d b e

1) 0

Answered by kaivan.ahmadi last updated on 23/Jan/19

let d ((3, 4), (x, y)) = 2 \Rightarrow

\sqrt{{(x - 3)}^{2} + {(y - 4)}^{2}} = 2 \Rightarrow {(x - 3)}^{2} + {(y - 4)}^{2} = 4 \Rightarrow

x^{2} - 6 x + 9 + y^{2} - 8 y + 16 = 4 \Rightarrow

- 6 x - 8 y + 25 = 0

8 y + 6 x = 25

(8, 6) = 2 ∤ 25 \Rightarrow no point satisfies the equation

The answer is zero .

Commented by vajpaithegrate@gmail.com last updated on 24/Jan/19

tnq sir