Question-53792

Question Number 53792 by behi83417@gmail.com last updated on 25/Jan/19

Commented by behi83417@gmail.com last updated on 25/Jan/19

A \overset{▴}{B C}, e q u i l a t e r a l w i t h : A B = 1 .

c i r c l e w i t h r a d i u s : r = \frac{1}{2 π}, t a n g e n t s t o

A C a n d A B a t : D, E .

find \min distance of circle from vertices

of A \overset{▴}{B C} .

Commented by tanmay.chaudhury50@gmail.com last updated on 26/Jan/19

Commented by tanmay.chaudhury50@gmail.com last updated on 26/Jan/19

A (0, 0) B (\frac{1}{2}, \frac{\sqrt{3}}{2}) C (\frac{- 1}{2}, \frac{\sqrt{3}}{2})

c e n t r e o f c i r c l e o n y a x i s (0, b)

s i n 30^{o} = \frac{r}{b} b = 2 r = 2 \times \frac{1}{2 π} = \frac{1}{π}

s o m i n i m u m d i s t a n c e = b = 2 r = \frac{1}{π}