Question Number 53907 by peter frank last updated on 27/Jan/19
Answered by ajfour last updated on 27/Jan/19
$${y}={ax}^{\mathrm{2}} \\ $$$$\mathrm{0}.\mathrm{1}=\left(\frac{\mathrm{5}}{\mathrm{2}}\right)^{\mathrm{2}} {a}\:\:\:\Rightarrow\:\:{a}=\frac{\mathrm{2}}{\mathrm{125}} \\ $$$${y}=\frac{\mathrm{2}}{\mathrm{125}}{x}^{\mathrm{2}} \\ $$$${No}\:{need}\:{of}\:{above}\:{calculations} \\ $$$${y}_{?} \:\approx\:\mathrm{4}{m}. \\ $$
Commented by peter frank last updated on 27/Jan/19
$${thank}\:{you}\:{sir} \\ $$