Question Number 53919 by byaw last updated on 27/Jan/19
Answered by $@ty@m last updated on 27/Jan/19
$${ATQ} \\ $$$$\mathrm{6}\:{oxen}\equiv\mathrm{8}\:{cows} \\ $$$$\Rightarrow\mathrm{1}\:{ox}\equiv\frac{\mathrm{8}}{\mathrm{6}}=\frac{\mathrm{4}}{\mathrm{3}}\:{cows} \\ $$$$\therefore\:\mathrm{9}\:{oxen}+\mathrm{2}\:{cows} \\ $$$$=\left(\mathrm{9}×\frac{\mathrm{4}}{\mathrm{3}}+\mathrm{2}\right){cows} \\ $$$$=\mathrm{14}\:{cows} \\ $$$$\mathrm{8}\:{cows}\:{can}\:{graze}\:{in}\:\mathrm{28}\:{days}. \\ $$$$\Rightarrow\mathrm{1}\:{cow}\:{can}\:{graze}\:{in}\:\mathrm{28}×\mathrm{8}\:{days}. \\ $$$$\Rightarrow\mathrm{14}\:{cow}\:{can}\:{graze}\:{in}\:\frac{\mathrm{28}×\mathrm{8}}{\mathrm{14}}\:{days}. \\ $$$$=\mathrm{16}\:{days}. \\ $$
Commented by byaw last updated on 27/Jan/19
$$\mathrm{Thank}\:\mathrm{you}\:\mathrm{very}\:\mathrm{much} \\ $$