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Question-54869




Question Number 54869 by peter frank last updated on 13/Feb/19
Answered by $@ty@m last updated on 13/Feb/19
Given β=(1/α) ⇒αβ=1  ⇒((10)/(3k+4))=1  ⇒3k+4=10  ⇒k=2
$${Given}\:\beta=\frac{\mathrm{1}}{\alpha}\:\Rightarrow\alpha\beta=\mathrm{1} \\ $$$$\Rightarrow\frac{\mathrm{10}}{\mathrm{3}{k}+\mathrm{4}}=\mathrm{1} \\ $$$$\Rightarrow\mathrm{3}{k}+\mathrm{4}=\mathrm{10} \\ $$$$\Rightarrow{k}=\mathrm{2} \\ $$

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