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Question-55300




Question Number 55300 by Tawa1 last updated on 20/Feb/19
Answered by tanmay.chaudhury50@gmail.com last updated on 21/Feb/19
p=2(2x+x)  (dp/dt)=6(dx/dt)  A=2x×x=2x^2   (dA/dt)=4x×(dx/dt)  18=4×1×(dx/dt) [2x=2 length given]  (dx/dt)=(9/2)  so (dp/dt)=6×(9/2)=27m/sec
$${p}=\mathrm{2}\left(\mathrm{2}{x}+{x}\right) \\ $$$$\frac{{dp}}{{dt}}=\mathrm{6}\frac{{dx}}{{dt}} \\ $$$${A}=\mathrm{2}{x}×{x}=\mathrm{2}{x}^{\mathrm{2}} \\ $$$$\frac{{dA}}{{dt}}=\mathrm{4}{x}×\frac{{dx}}{{dt}} \\ $$$$\mathrm{18}=\mathrm{4}×\mathrm{1}×\frac{{dx}}{{dt}}\:\left[\mathrm{2}{x}=\mathrm{2}\:{length}\:{given}\right] \\ $$$$\frac{{dx}}{{dt}}=\frac{\mathrm{9}}{\mathrm{2}} \\ $$$${so}\:\frac{{dp}}{{dt}}=\mathrm{6}×\frac{\mathrm{9}}{\mathrm{2}}=\mathrm{27}{m}/{sec} \\ $$
Commented by Tawa1 last updated on 21/Feb/19
God bless you sir
$$\mathrm{God}\:\mathrm{bless}\:\mathrm{you}\:\mathrm{sir} \\ $$

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