Question-55375

Question Number 55375 by Tawa1 last updated on 23/Feb/19

Commented by tanmay.chaudhury50@gmail.com last updated on 23/Feb/19

p l s s p e c i f y t h e p o i n t o f a p p l i c s t i o n o f f o r c e

o n a x l e \dots

Answered by mr W last updated on 23/Feb/19

I α = {F r}_{A}

\Rightarrow α = \frac{{F r}_{A}}{I}

ω = α t = \frac{{F r}_{A} t}{I}

K E = \frac{I ω^{2}}{2} = \frac{{({F r}_{A} t)}^{2}}{2 I} = \frac{{({F r}_{A} t)}^{2}}{2 \times \frac{{m r}_{D}^{2}}{2}}

= \frac{1}{m} {(\frac{{F t r}_{A}}{r_{D}})}^{2}

= \frac{1}{20} {(\frac{12 \times 1.2 \times 1.5}{15})}^{2}

= 0.104 J

Commented by Tawa1 last updated on 23/Feb/19

God bless you sir, i appreciate .

Commented by Tawa1 last updated on 23/Feb/19

Sir, please see question 55412, help me use lambert W function .

Commented by mr W last updated on 23/Feb/19

Commented by mr W last updated on 23/Feb/19

i t c a n n o t b e s o l v e d a n a l y t i c a l l y .

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