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Question-55449




Question Number 55449 by ketto2 last updated on 24/Feb/19
Answered by Kunal12588 last updated on 24/Feb/19
16y^2 +xy−15x^2   =16y^2 +16xy−15xy−15x^2   =16y(y+x)−15x(y+x)  =(16y−15x)(x+y)
$$\mathrm{16}{y}^{\mathrm{2}} +{xy}−\mathrm{15}{x}^{\mathrm{2}} \\ $$$$=\mathrm{16}{y}^{\mathrm{2}} +\mathrm{16}{xy}−\mathrm{15}{xy}−\mathrm{15}{x}^{\mathrm{2}} \\ $$$$=\mathrm{16}{y}\left({y}+{x}\right)−\mathrm{15}{x}\left({y}+{x}\right) \\ $$$$=\left(\mathrm{16}{y}−\mathrm{15}{x}\right)\left({x}+{y}\right) \\ $$

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