Question Number 55458 by Gulay last updated on 24/Feb/19
Commented by Gulay last updated on 24/Feb/19
$$\mathrm{sir}\:\mathrm{plz}\:\mathrm{help}\:\mathrm{me} \\ $$
Answered by tanmay.chaudhury50@gmail.com last updated on 24/Feb/19
$$\mathrm{2}{log}_{\mathrm{3}} \left({x}−\mathrm{4}\right)^{\mathrm{2}} ={xlog}_{\mathrm{3}} \left(\mathrm{4}−{x}\right) \\ $$$${log}_{\mathrm{3}} \left({x}−\mathrm{4}\right)^{\mathrm{4}} ={log}_{\mathrm{3}} \left(\mathrm{4}−{x}\right)^{{x}} \\ $$$$\left({x}−\mathrm{4}\right)^{\mathrm{4}} =\left(\mathrm{4}−{x}\right)^{{x}} \\ $$$$\left(\mathrm{4}−{x}\right)^{\mathrm{4}} =\left(\mathrm{4}−{x}\right)^{{x}} \:\left[{since}\:\left({x}−\mathrm{4}\right)^{\mathrm{4}} =\left(\mathrm{4}−{x}\right)^{\mathrm{4}} \right] \\ $$$$\mathrm{4}={x} \\ $$$${x}=\mathrm{4} \\ $$$$ \\ $$$$ \\ $$
Commented by Gulay last updated on 25/Feb/19
$$\mathrm{thanks}\:\mathrm{sir} \\ $$