Question-55748

Question Number 55748 by necx1 last updated on 03/Mar/19

Commented by necx1 last updated on 03/Mar/19

p l e a s e h e l p

Answered by tanmay.chaudhury50@gmail.com last updated on 03/Mar/19

h ν = h ν_{o} + \frac{1}{2} {m v}_{m a x}^{2}

\frac{h c}{λ} = \frac{h c}{λ_{o}} + \frac{1}{2} {m v}_{m a x}^{2}

λ = 2000 \times 10^{- 10} m e t e r

i t h i n k λ_{0} = 4400 \times 10^{- 10} m e t e r

{(K . E)}_{m a x} = h c (\frac{1}{λ} - \frac{1}{λ_{0}})

b) ★ p l s c h e c k \dots

c h a n g e o f k i n e t i c e n e r g y = w o r k d o n e

c h a r g e \times p o t e n t i a l d i f f e r e n c e = (\frac{1}{2} {m c}^{2} - 0)

e v = \frac{1}{2} {m c}^{2}

v = \frac{{m c}^{2}}{2 e} ★

Commented by necx1 last updated on 03/Mar/19

e x a x t l y! T h a n k y o u s o m u c h

Facebook Tweet Pin