Question Number 55805 by bshahid010@gmail.com last updated on 04/Mar/19
![](https://www.tinkutara.com/question/7426.png)
Commented by MJS last updated on 04/Mar/19
![b=0 ⇒ ((a^2 +b^2 )/(ab+1))=a^2 b=a^3 ⇒ ((a^2 +b^2 )/(ab+1))=a^2 but I′m not sure if there are other possible values for b](https://www.tinkutara.com/question/Q55812.png)
$$\mathrm{b}=\mathrm{0}\:\Rightarrow\:\frac{{a}^{\mathrm{2}} +{b}^{\mathrm{2}} }{{ab}+\mathrm{1}}={a}^{\mathrm{2}} \\ $$$${b}={a}^{\mathrm{3}} \:\Rightarrow\:\frac{{a}^{\mathrm{2}} +{b}^{\mathrm{2}} }{{ab}+\mathrm{1}}={a}^{\mathrm{2}} \\ $$$$\mathrm{but}\:\mathrm{I}'\mathrm{m}\:\mathrm{not}\:\mathrm{sure}\:\mathrm{if}\:\mathrm{there}\:\mathrm{are}\:\mathrm{other}\:\mathrm{possible} \\ $$$$\mathrm{values}\:\mathrm{for}\:{b} \\ $$