Question Number 55954 by Easyman32 last updated on 06/Mar/19
Answered by MJS last updated on 06/Mar/19
$$\mathrm{draw}\:\mathrm{them}:\:\mathrm{2}\:\mathrm{half}\:\mathrm{parabolas}\:\Rightarrow \\ $$$$\Rightarrow\:\mathrm{1}\:\mathrm{intersection} \\ $$$${x}=\mathrm{11}.\mathrm{932};\:{y}=\mathrm{16}.\mathrm{546} \\ $$
Commented by MJS last updated on 07/Mar/19
$$\mathrm{the}\:\mathrm{occuring}\:\mathrm{polynomial}\:\mathrm{of}\:\mathrm{4}^{\mathrm{th}} \:\mathrm{degree}\:\mathrm{hasn}'\mathrm{t} \\ $$$$\mathrm{got}\:\mathrm{any}\:\mathrm{useable}\:\mathrm{exact}\:\mathrm{solution} \\ $$