Question-55970

Question Number 55970 by necx1 last updated on 07/Mar/19

Answered by tanmay.chaudhury50@gmail.com last updated on 07/Mar/19

10 μ F a n d 10 μ F a r e p a r a l l e l

s o 10 + 10 = 20 μ F

15 μ F a n d 5 μ F a r e p a r a l l e l

s o 15 + 5 = 20 μ F

n o w t h i s 20 μ F a n d 20 μ F a r e s e r i e s

c_{e q} = \frac{1}{\frac{1}{20} + \frac{1}{20}} = \frac{20}{2} = 10 μ F

n o w t h i s 10 μ F a n d 20 μ F a r e p a r a l l e l

s o 10 + 20 = 30 μ F

Q c h a r g e = 30 \times 10^{- 6} \times 10 = 300 \times 10^{- 6} C o l u m b \dots

C_{15} : C_{5} : C_{20} = 15 : 5 : 20 = 3 : 1 : 4

s o i t h i n k c h a r g e o n 5 μ F

i s = \frac{1}{3 + 1 + 4} \times 300 \times 10^{- 6} = 37.5 \times 10^{- 6} C

P l s c o m m e n t a n d r e c t i f y i f i a m w r o n g \dots