Question Number 56165 by Tawa1 last updated on 11/Mar/19
Answered by tanmay.chaudhury50@gmail.com last updated on 11/Mar/19
$${A}=\mathrm{6}{cos}\mathrm{36}^{\mathrm{0}} {i}+\mathrm{6}{sin}\mathrm{36}^{{o}} {j} \\ $$$${B}=−\mathrm{7}{i} \\ $$$${A}+{B}=\left(\mathrm{6}{cos}\mathrm{36}^{{o}} −\mathrm{7}\right){i}+\mathrm{6}{sin}\mathrm{36}^{\mathrm{0}} {j} \\ $$$${A}−{B}=\left(\mathrm{6}{cos}\mathrm{36}+\mathrm{7}\right){i}+\mathrm{6}{sin}\mathrm{36}{j} \\ $$$$\mid{A}+{B}\mid^{\mid} =\sqrt{\left(\mathrm{6}{cos}\mathrm{36}^{\mathrm{0}} −\mathrm{7}\right)^{\mathrm{2}} +\left(\mathrm{6}{sin}\mathrm{36}^{{o}} \right)^{\mathrm{2}} } \\ $$$$=\sqrt{\mathrm{6}^{\mathrm{2}} +\mathrm{7}^{\mathrm{2}} −\mathrm{2}×\mathrm{6}×\mathrm{7}{cos}\mathrm{36}^{{o}} }\: \\ $$$$\mid{A}−{B}\mid=\sqrt{\mathrm{6}^{\mathrm{2}} +\mathrm{7}^{\mathrm{2}} +\mathrm{2}×\mathrm{6}×\mathrm{7}{cos}\mathrm{36}_{} ^{{o}} }\: \\ $$
Commented by Tawa1 last updated on 11/Mar/19
$$\mathrm{God}\:\mathrm{bless}\:\mathrm{you}\:\mathrm{sir}.\:\mathrm{I}\:\mathrm{appreciate} \\ $$