Question Number 56578 by Tinkutara last updated on 18/Mar/19
Commented by Tinkutara last updated on 18/Mar/19
Q1
Commented by mr W last updated on 19/Mar/19
$${Energy}=\frac{\mathrm{1}}{\mathrm{2}}{kx}^{\mathrm{2}} =\frac{\mathrm{1}}{\mathrm{2}}\left(\mathrm{4}{k}\right){y}^{\mathrm{2}} \\ $$$$\Rightarrow\frac{{y}}{{x}}=\frac{\mathrm{1}}{\mathrm{2}} \\ $$$$\Rightarrow{answer}\:\left({c}\right) \\ $$
Commented by Tinkutara last updated on 31/Mar/19
Thank you so much Sir!