Question-56874 Tinku Tara June 4, 2023 Mechanics 0 Comments FacebookTweetPin Question Number 56874 by Runzzy last updated on 25/Mar/19 Answered by tanmay.chaudhury50@gmail.com last updated on 26/Mar/19 FR=(0.2)2+(0.3)2+2×0.2×0.3cos95o=0.3457≈0.346Fx={0.2cos25o−0.3cos(180o−95o−25o)}i=0.2cos25o−0.3cos60o=0.1812615574−0.15=0.0312615574iFy={0.2sin25o+0.3sin60o}×−j=−(0.3443312735)jtanβ=FyFx Terms of Service Privacy Policy Contact: info@tinkutara.com FacebookTweetPin Post navigation Previous Previous post: Question-187947Next Next post: please-help-me-to-solve-6x-2-x-2-0- Leave a Reply Cancel replyYour email address will not be published. Required fields are marked *Comment * Name * Save my name, email, and website in this browser for the next time I comment.