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Question-58051




Question Number 58051 by Aditya789 last updated on 17/Apr/19
Answered by tanmay last updated on 17/Apr/19
sample space{HHH,HHT,HTH,HTT,THH       THT,TTH,TTT}  favourabe result is{HTH^� ,THT}  so probablity=(2/8)=(1/4)
$${sample}\:{space}\left\{{HHH},{HHT},{HTH},{HTT},{THH}\right. \\ $$$$\left.\:\:\:\:\:{THT},{TTH},{TTT}\right\} \\ $$$${favourabe}\:{result}\:{is}\left\{{HT}\bar {{H}},{THT}\right\} \\ $$$${so}\:{probablity}=\frac{\mathrm{2}}{\mathrm{8}}=\frac{\mathrm{1}}{\mathrm{4}} \\ $$

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