Question Number 58626 by rahul 19 last updated on 26/Apr/19
Commented by rahul 19 last updated on 26/Apr/19
$${Ans}:\:{a},{c},{d} \\ $$
Answered by tanmay last updated on 26/Apr/19
$${f}\left({x}\right)=\sqrt{\mathrm{3}+{x}^{\mathrm{3}} }\:\:{f}\left(\mathrm{1}\right)=\mathrm{2}\:\:\:{m}=\mathrm{2} \\ $$$${f}\left(\mathrm{3}\right)=\sqrt{\mathrm{30}}\:\:{M}=\sqrt{\mathrm{30}}\: \\ $$$$\int_{\mathrm{1}} ^{\mathrm{3}} \sqrt{\mathrm{30}}\:{dx}>\int_{\mathrm{1}} ^{\mathrm{3}} \sqrt{\mathrm{3}+{x}^{\mathrm{3}} }\:{dx}>\mathrm{2}\int_{\mathrm{1}} ^{\mathrm{3}} {dx} \\ $$$$\mathrm{2}\sqrt{\mathrm{30}}\:>\int_{\mathrm{1}} ^{\mathrm{3}} \sqrt{\mathrm{3}+{x}^{\mathrm{3}} }\:{dx}>\mathrm{2}\left(\mathrm{2}\right) \\ $$$$\mathrm{2}\sqrt{\mathrm{30}}\:>\int_{\mathrm{1}} ^{\mathrm{3}} \sqrt{\mathrm{3}+{x}^{\mathrm{3}} }\:{dx}>\mathrm{4} \\ $$$$ \\ $$
Commented by tanmay last updated on 26/Apr/19
Commented by rahul 19 last updated on 26/Apr/19
$${thank}\:{U}\:{sir}. \\ $$