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Question-58974




Question Number 58974 by Tawa1 last updated on 02/May/19
Answered by MJS last updated on 03/May/19
((3.86km)/(x((km)/(hr))))+((180.2km)/(10x((km)/(hr))))+((42.2km)/(5x((km)/(hr))))=16.2hr  ((3.86)/x)hr+((180.2)/(10x))hr+((42.2)/(5x))hr=16.2hr  ((3.86)/x)+((18.02)/x)+((8.44)/x)=16.2  3.86+18.02+8.44=16.2x  x=((30.32)/(16.2))=((758)/(405))≈1.87  he swims 1.87km/hr  he bikes 18.72km/hr  he runs 9.36km/hr
$$\frac{\mathrm{3}.\mathrm{86km}}{{x}\frac{\mathrm{km}}{\mathrm{hr}}}+\frac{\mathrm{180}.\mathrm{2km}}{\mathrm{10}{x}\frac{\mathrm{km}}{\mathrm{hr}}}+\frac{\mathrm{42}.\mathrm{2km}}{\mathrm{5}{x}\frac{\mathrm{km}}{\mathrm{hr}}}=\mathrm{16}.\mathrm{2hr} \\ $$$$\frac{\mathrm{3}.\mathrm{86}}{{x}}\mathrm{hr}+\frac{\mathrm{180}.\mathrm{2}}{\mathrm{10}{x}}\mathrm{hr}+\frac{\mathrm{42}.\mathrm{2}}{\mathrm{5}{x}}\mathrm{hr}=\mathrm{16}.\mathrm{2hr} \\ $$$$\frac{\mathrm{3}.\mathrm{86}}{{x}}+\frac{\mathrm{18}.\mathrm{02}}{{x}}+\frac{\mathrm{8}.\mathrm{44}}{{x}}=\mathrm{16}.\mathrm{2} \\ $$$$\mathrm{3}.\mathrm{86}+\mathrm{18}.\mathrm{02}+\mathrm{8}.\mathrm{44}=\mathrm{16}.\mathrm{2}{x} \\ $$$${x}=\frac{\mathrm{30}.\mathrm{32}}{\mathrm{16}.\mathrm{2}}=\frac{\mathrm{758}}{\mathrm{405}}\approx\mathrm{1}.\mathrm{87} \\ $$$$\mathrm{he}\:\mathrm{swims}\:\mathrm{1}.\mathrm{87km}/\mathrm{hr} \\ $$$$\mathrm{he}\:\mathrm{bikes}\:\mathrm{18}.\mathrm{72km}/\mathrm{hr} \\ $$$$\mathrm{he}\:\mathrm{runs}\:\mathrm{9}.\mathrm{36km}/\mathrm{hr} \\ $$
Commented by Tawa1 last updated on 03/May/19
God bless you sir. i appreciate
$$\mathrm{God}\:\mathrm{bless}\:\mathrm{you}\:\mathrm{sir}.\:\mathrm{i}\:\mathrm{appreciate} \\ $$

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