Question Number 59595 by Gulay last updated on 12/May/19
Commented by Gulay last updated on 12/May/19
$$\mathrm{sir}\:\mathrm{could}\:\mathrm{you}\:\mathrm{belp}\:\mathrm{me} \\ $$
Answered by tanmay last updated on 12/May/19
$$\underset{{x}\rightarrow\mathrm{4}} {\mathrm{lim}}\left(\frac{{x}+\mathrm{4}−\mathrm{8}}{{x}^{\mathrm{2}} −\mathrm{16}}\right) \\ $$$$\underset{{x}\rightarrow\mathrm{4}} {\mathrm{lim}}\left\{\frac{{x}−\mathrm{4}}{\left({x}+\mathrm{4}\right)\left({x}−\mathrm{4}\right)}\right\} \\ $$$$=\frac{\mathrm{1}}{\mathrm{4}+\mathrm{4}} \\ $$$$=\frac{\mathrm{1}}{\mathrm{8}} \\ $$