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Question-59703




Question Number 59703 by ranusahu last updated on 13/May/19
Answered by ajfour last updated on 13/May/19
2kx_0 =((Qq)/(2π^2 ε_0 a^2 ))  x_0 =((Qq)/(4π^2 ε_0 a^2 k))          (B)
2kx0=Qq2π2ϵ0a2x0=Qq4π2ϵ0a2k(B)
Commented by ranusahu last updated on 14/May/19
please explain in  detail
pleaseexplainindetail

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