Question Number 59703 by ranusahu last updated on 13/May/19
Answered by ajfour last updated on 13/May/19
$$\mathrm{2kx}_{\mathrm{0}} =\frac{\mathrm{Qq}}{\mathrm{2}\pi^{\mathrm{2}} \epsilon_{\mathrm{0}} \mathrm{a}^{\mathrm{2}} } \\ $$$$\mathrm{x}_{\mathrm{0}} =\frac{\mathrm{Qq}}{\mathrm{4}\pi^{\mathrm{2}} \epsilon_{\mathrm{0}} \mathrm{a}^{\mathrm{2}} \mathrm{k}}\:\:\:\:\:\:\:\:\:\:\left(\mathrm{B}\right) \\ $$
Commented by ranusahu last updated on 14/May/19
$$\mathrm{please}\:\mathrm{explain}\:\mathrm{in}\:\:\mathrm{detail} \\ $$