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Question-59960




Question Number 59960 by cesar.marval.larez@gmail.com last updated on 16/May/19
Answered by MJS last updated on 16/May/19
I don′t understand the question  is A the source or the target of the vectors?  if it′s the source  X=A+v^(→) =(a, b)+(v, w)=(a+v, b+w)  if it′s the target  X+v^(→) =A ⇒ X=A−v^(→) =(a, b)−(v, w)=(a−v, b−w)
$$\mathrm{I}\:\mathrm{don}'\mathrm{t}\:\mathrm{understand}\:\mathrm{the}\:\mathrm{question} \\ $$$$\mathrm{is}\:{A}\:\mathrm{the}\:\mathrm{source}\:\mathrm{or}\:\mathrm{the}\:\mathrm{target}\:\mathrm{of}\:\mathrm{the}\:\mathrm{vectors}? \\ $$$$\mathrm{if}\:\mathrm{it}'\mathrm{s}\:\mathrm{the}\:\mathrm{source} \\ $$$${X}={A}+\overset{\rightarrow} {\mathfrak{v}}=\left({a},\:{b}\right)+\left({v},\:{w}\right)=\left({a}+{v},\:{b}+{w}\right) \\ $$$$\mathrm{if}\:\mathrm{it}'\mathrm{s}\:\mathrm{the}\:\mathrm{target} \\ $$$${X}+\overset{\rightarrow} {\mathfrak{v}}={A}\:\Rightarrow\:{X}={A}−\overset{\rightarrow} {\mathfrak{v}}=\left({a},\:{b}\right)−\left({v},\:{w}\right)=\left({a}−{v},\:{b}−{w}\right) \\ $$

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