Question Number 60347 by ANTARES VY last updated on 20/May/19
Commented by ANTARES VY last updated on 20/May/19
$$\boldsymbol{\mathrm{calculate}} \\ $$
Answered by mr W last updated on 20/May/19
$${x}=\sqrt{\mathrm{2}^{\mathrm{3}} \sqrt{\mathrm{5}^{\mathrm{3}} {x}}} \\ $$$${x}^{\mathrm{2}} =\mathrm{2}^{\mathrm{3}} \sqrt{\mathrm{5}^{\mathrm{3}} {x}} \\ $$$${x}^{\mathrm{4}} =\mathrm{2}^{\mathrm{6}} ×\mathrm{5}^{\mathrm{3}} {x} \\ $$$${x}^{\mathrm{3}} =\mathrm{2}^{\mathrm{6}} ×\mathrm{5}^{\mathrm{3}} \\ $$$$\Rightarrow{x}=\mathrm{2}^{\mathrm{2}} ×\mathrm{5}=\mathrm{20} \\ $$$$\Rightarrow{answer}\:{D} \\ $$