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Question-60588

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Question Number 60588 by behi83417@gmail.com last updated on 22/May/19
Commented by behi83417@gmail.com last updated on 22/May/19
AD &CE are angular bisector of ∡A &∡C. DG⊥AB,EF⊥BC,BH⊥DE,DE=(1/2)AC. ⇒((BH)/(DG+EF))=?
AD&CEareangularbisectorof∡A&∡C.DG⊥AB,EF⊥BC,BH⊥DE,DE=12AC.⇒BHDG+EF=?

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