Question Number 61048 by Gulay last updated on 28/May/19
Commented by Gulay last updated on 28/May/19
$$\mathrm{AB}=\mathrm{30}\:\:\:\:\mathrm{BD}=\mathrm{24}\:\:\:\mathrm{Find}\:\mathrm{DC}\:\:\:<\mathrm{B}=\mathrm{90} \\ $$$$\mathrm{sir}\:\mathrm{plz}\:\mathrm{help}\:\mathrm{me} \\ $$
Answered by mr W last updated on 28/May/19
$${AD}=\sqrt{{AB}^{\mathrm{2}} −{BD}^{\mathrm{2}} }=\sqrt{\mathrm{30}^{\mathrm{2}} −\mathrm{24}^{\mathrm{2}} }=\mathrm{18} \\ $$$$\frac{{DC}}{{BD}}=\frac{{BD}}{{AD}} \\ $$$$\Rightarrow{DC}=\frac{{BD}^{\mathrm{2}} }{{AD}}=\frac{\mathrm{24}^{\mathrm{2}} }{\mathrm{18}}=\mathrm{32} \\ $$
Commented by kaivan.ahmadi last updated on 28/May/19