Question Number 61061 by Gulay last updated on 28/May/19
Commented by Gulay last updated on 28/May/19
$$\mathrm{AB}=\mathrm{6}\:\:\mathrm{AC}=\mathrm{12}\:\mathrm{and}\:\mathrm{BC}=\mathrm{15}\:\:\mathrm{Find} \\ $$$$\frac{\mathrm{Saec}}{\mathrm{Sedc}} \\ $$
Answered by ajfour last updated on 28/May/19
$$\frac{{S}_{{AEC}} }{{S}_{{EDC}} }=\frac{{AE}}{{ED}}=\frac{{AC}}{{CD}}\:=\:\frac{{AC}}{\frac{\mathrm{2}}{\mathrm{3}}{BC}}=\frac{\mathrm{12}}{\mathrm{10}}=\frac{\mathrm{6}}{\mathrm{5}}. \\ $$
Commented by Gulay last updated on 28/May/19
$$\mathrm{thank}\:\mathrm{you}\:\mathrm{so}\:\mathrm{muchhh}\:\mathrm{sir} \\ $$