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Question-61116




Question Number 61116 by Kunal12588 last updated on 29/May/19
Answered by ajfour last updated on 29/May/19
If g=10m/s^2   then in the last second distance  traveled is  (1/2)gt^2 = 5m  irrespective of the value of u.  Only u should be such that it  goes at least 5m high; ⇒ u≥10m/s.
$${If}\:{g}=\mathrm{10}{m}/{s}^{\mathrm{2}} \\ $$$${then}\:{in}\:{the}\:{last}\:{second}\:{distance} \\ $$$${traveled}\:{is}\:\:\frac{\mathrm{1}}{\mathrm{2}}{gt}^{\mathrm{2}} =\:\mathrm{5}{m} \\ $$$${irrespective}\:{of}\:{the}\:{value}\:{of}\:{u}. \\ $$$${Only}\:{u}\:{should}\:{be}\:{such}\:{that}\:{it} \\ $$$${goes}\:{at}\:{least}\:\mathrm{5}{m}\:{high};\:\Rightarrow\:{u}\geqslant\mathrm{10}{m}/{s}. \\ $$
Commented by Kunal12588 last updated on 29/May/19
thanks sir. I never thought answer would be  like this.
$${thanks}\:{sir}.\:{I}\:{never}\:{thought}\:{answer}\:{would}\:{be} \\ $$$${like}\:{this}. \\ $$

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