Question Number 61202 by aanur last updated on 30/May/19
Commented by aanur last updated on 30/May/19
$${a}=\mathrm{73}\frac{\mathrm{5}}{\mathrm{7}}\:\:\:\:\:{b}=\mathrm{31}\frac{\mathrm{2}}{\mathrm{7}} \\ $$$${sir}\:{help}\:{me}\:{plz} \\ $$
Answered by Kunal12588 last updated on 30/May/19
$${a}=\mathrm{73}\frac{\mathrm{5}}{\mathrm{7}},\:{b}=\mathrm{31}\frac{\mathrm{2}}{\mathrm{7}} \\ $$$${a}^{\mathrm{2}} +\mathrm{2}{ab}+{b}^{\mathrm{2}} −\mathrm{25} \\ $$$$=\left({a}+{b}\right)^{\mathrm{2}} −\left(\mathrm{5}\right)^{\mathrm{2}} \\ $$$$=\left({a}+{b}−\mathrm{5}\right)\left({a}+{b}+\mathrm{5}\right) \\ $$$$=\left(\mathrm{73}\frac{\mathrm{5}}{\mathrm{7}}+\mathrm{31}\frac{\mathrm{2}}{\mathrm{7}}−\mathrm{5}\right)\left(\mathrm{73}\frac{\mathrm{5}}{\mathrm{7}}+\mathrm{31}\frac{\mathrm{2}}{\mathrm{7}}+\mathrm{5}\right) \\ $$$$=\left(\mathrm{105}−\mathrm{5}\right)\left(\mathrm{105}+\mathrm{5}\right) \\ $$$$=\left(\mathrm{100}\right)\left(\mathrm{110}\right) \\ $$$$=\mathrm{11000} \\ $$