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Question-61700




Question Number 61700 by aliesam last updated on 06/Jun/19
Answered by tanmay last updated on 06/Jun/19
a=−b−c  a^2 =−ab−ac  ((−ab−ac)/(−ab−bc−ac))+((−ab−bc)/(−ab−bc−ca))+((−ac−bc)/(−ac−bc−ab))  =((−2(ab+bc+ac))/(−(ab+bc+ac)))  =2
$${a}=−{b}−{c} \\ $$$${a}^{\mathrm{2}} =−{ab}−{ac} \\ $$$$\frac{−{ab}−{ac}}{−{ab}−{bc}−{ac}}+\frac{−{ab}−{bc}}{−{ab}−{bc}−{ca}}+\frac{−{ac}−{bc}}{−{ac}−{bc}−{ab}} \\ $$$$=\frac{−\mathrm{2}\left({ab}+{bc}+{ac}\right)}{−\left({ab}+{bc}+{ac}\right)} \\ $$$$=\mathrm{2} \\ $$

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