Question-61825

Question Number 61825 by Tawa1 last updated on 09/Jun/19

Answered by mr W last updated on 10/Jun/19

Commented by mr W last updated on 10/Jun/19

\frac{q}{4} = \frac{p}{7}

\Rightarrow q = \frac{4 p}{7}

\frac{4 + p}{a} = \frac{7 + q}{9}

\Rightarrow 9 (4 + p) = a (7 + q)

\Rightarrow 36 + 9 p = 7 a + \frac{4 a p}{7}

\Rightarrow p = \frac{49 a - 252}{63 - 4 a}

\frac{q \times a}{4} + \sqrt{7^{2} - p^{2}} = 9

\Rightarrow \frac{a p}{7} + \sqrt{7^{2} - p^{2}} = 9

\Rightarrow \frac{a (49 a - 252)}{7 (63 - 4 a)} + \sqrt{49 - {(\frac{49 a - 252}{63 - 4 a})}^{2}} = 9

\Rightarrow a \approx 6.9282

A_{g r e e n} = \frac{7 \times a}{2} \approx 24.25

Commented by Tawa1 last updated on 10/Jun/19

God bless you sir

Commented by MJS last updated on 10/Jun/19

the red eq can be solved exactly

a = \pm 4 \sqrt{3} \lor a = \pm 9

4 \sqrt{3} \approx 6.9282

Commented by mr W last updated on 10/Jun/19

t h a n k y o u s i r!

i {d i d n}^{'} t g o f u r t h e r, s i n c e i t l e d t o a

q u a d r a t i c e q u a t i o n .

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