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Question-64240




Question Number 64240 by harish kumar last updated on 16/Jul/19
Answered by Tanmay chaudhury last updated on 16/Jul/19
4x^2 −y^2 +2x−2y−3xy  4x^2 −3xy−y^2 +2(x−y)  =4x^2 −4xy+xy−y^2 +2(x−y)  =4x(x−y)+y(x−y)+2(x−y)  =(x−y)(4x+y+2)  Tanmay 16.07.19
$$\mathrm{4}{x}^{\mathrm{2}} −{y}^{\mathrm{2}} +\mathrm{2}{x}−\mathrm{2}{y}−\mathrm{3}{xy} \\ $$$$\mathrm{4}{x}^{\mathrm{2}} −\mathrm{3}{xy}−{y}^{\mathrm{2}} +\mathrm{2}\left({x}−{y}\right) \\ $$$$=\mathrm{4}{x}^{\mathrm{2}} −\mathrm{4}{xy}+{xy}−{y}^{\mathrm{2}} +\mathrm{2}\left({x}−{y}\right) \\ $$$$=\mathrm{4}{x}\left({x}−{y}\right)+{y}\left({x}−{y}\right)+\mathrm{2}\left({x}−{y}\right) \\ $$$$=\left({x}−{y}\right)\left(\mathrm{4}{x}+{y}+\mathrm{2}\right)\:\:{Tanmay}\:\mathrm{16}.\mathrm{07}.\mathrm{19} \\ $$

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