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Question-65113

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Question Number 65113 by rajesh4661kumar@gamil.com last updated on 25/Jul/19
Commented by Prithwish sen last updated on 25/Jul/19
No. of term on n^(tn) group = 2n−1 The 1^(st ) term of the n^(th ) group = (((n−1))/2)[2+(n−2)2] +1 = (n−1)^2 +1 =n^2 −2n+2 ∴ the sum of n^(th) group =(((2n−1))/2)[2(n^2 −2n+2)+(2n−2)] = (2n−1)(n^2 −n+1) = (n−1)^3 + n^3 please check.
No.oftermonntngroup=2n−1The1sttermofthenthgroup=(n−1)2[2+(n−2)2]+1=(n−1)2+1=n2−2n+2∴thesumofnthgroup=(2n−1)2[2(n2−2n+2)+(2n−2)]=(2n−1)(n2−n+1)=(n−1)3+n3pleasecheck.

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