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Question-80204




Question Number 80204 by jagoll last updated on 01/Feb/20
Commented by Tony Lin last updated on 01/Feb/20
28(x+y+z)=363+(x−z)  if x+y+z≥14  x−z≥29>x+y+z(false)  if x+y+z=13  then x−z=1<x+y+z  if x+y+z≤12  z−x≥27>x+y+z(false)  therefore  10x+10y+10z=130
28(x+y+z)=363+(xz)ifx+y+z14xz29>x+y+z(false)ifx+y+z=13thenxz=1<x+y+zifx+y+z12zx27>x+y+z(false)therefore10x+10y+10z=130
Commented by jagoll last updated on 01/Feb/20
thank you sir
thankyousir

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