Question Number 80620 by M±th+et£s last updated on 04/Feb/20
Commented by mr W last updated on 04/Feb/20
$$\mathrm{25}×\mathrm{1}.\mathrm{2}×\mathrm{10}^{−\mathrm{5}} ×\mathrm{200}×\mathrm{10}^{\mathrm{9}} =\mathrm{6}×\mathrm{10}^{\mathrm{7}} \:{N}/{m}^{\mathrm{2}} \\ $$$$\frac{\mathrm{6}}{\mathrm{52}.\mathrm{2}}=\mathrm{11}.\mathrm{5\%} \\ $$