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Question-80620




Question Number 80620 by M±th+et£s last updated on 04/Feb/20
Commented by mr W last updated on 04/Feb/20
25×1.2×10^(−5) ×200×10^9 =6×10^7  N/m^2   (6/(52.2))=11.5%
$$\mathrm{25}×\mathrm{1}.\mathrm{2}×\mathrm{10}^{−\mathrm{5}} ×\mathrm{200}×\mathrm{10}^{\mathrm{9}} =\mathrm{6}×\mathrm{10}^{\mathrm{7}} \:{N}/{m}^{\mathrm{2}} \\ $$$$\frac{\mathrm{6}}{\mathrm{52}.\mathrm{2}}=\mathrm{11}.\mathrm{5\%} \\ $$

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