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Question-80689




Question Number 80689 by ahmadshahhimat775@gmail.com last updated on 05/Feb/20
Commented by john santu last updated on 05/Feb/20
lim_(x→1)  ((20(x−1))/(ln(2x−1)))=lim_(x→1)  ((20)/(((2/(2x−1))))))  = lim_(x→1)  ((10(2x−1))/1)=10
$$\underset{{x}\rightarrow\mathrm{1}} {\mathrm{lim}}\:\frac{\mathrm{20}\left({x}−\mathrm{1}\right)}{{ln}\left(\mathrm{2}{x}−\mathrm{1}\right)}=\underset{{x}\rightarrow\mathrm{1}} {\mathrm{lim}}\:\frac{\mathrm{20}}{\left(\frac{\mathrm{2}}{\left.\mathrm{2}{x}−\mathrm{1}\right)}\right)} \\ $$$$=\:\underset{{x}\rightarrow\mathrm{1}} {\mathrm{lim}}\:\frac{\mathrm{10}\left(\mathrm{2}{x}−\mathrm{1}\right)}{\mathrm{1}}=\mathrm{10} \\ $$

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