Question Number 80689 by ahmadshahhimat775@gmail.com last updated on 05/Feb/20
Commented by john santu last updated on 05/Feb/20
$$\underset{{x}\rightarrow\mathrm{1}} {\mathrm{lim}}\:\frac{\mathrm{20}\left({x}−\mathrm{1}\right)}{{ln}\left(\mathrm{2}{x}−\mathrm{1}\right)}=\underset{{x}\rightarrow\mathrm{1}} {\mathrm{lim}}\:\frac{\mathrm{20}}{\left(\frac{\mathrm{2}}{\left.\mathrm{2}{x}−\mathrm{1}\right)}\right)} \\ $$$$=\:\underset{{x}\rightarrow\mathrm{1}} {\mathrm{lim}}\:\frac{\mathrm{10}\left(\mathrm{2}{x}−\mathrm{1}\right)}{\mathrm{1}}=\mathrm{10} \\ $$