Question Number 80930 by peter frank last updated on 08/Feb/20
Commented by jagoll last updated on 08/Feb/20
$$\Rightarrow\left(\mathrm{1}\right)\:{a}+{b}+\mathrm{2}\:=\:\mathrm{0}\:,\:{a}+{b}\:=\:−\mathrm{2} \\ $$$$\Rightarrow\left(\mathrm{2}\right)\:{y}'\:=\:\mathrm{3}{ax}^{\mathrm{2}} +\mathrm{2}{bx} \\ $$$$\Rightarrow{y}\:''\:=\:\mathrm{6}{ax}\:+\mathrm{2}{b}\:=\:\mathrm{0}\:{for}\:{x}\:=\:\mathrm{1} \\ $$$$\mathrm{2}{b}\:=\:−\mathrm{6}{a}\:\Rightarrow{b}\:=\:−\mathrm{3}{a}\:\wedge\:{a}+{b}\:=−\mathrm{2} \\ $$$$−\mathrm{2}{a}\:=\:−\mathrm{2}\:\Rightarrow{a}\:=\:\mathrm{1}\:\wedge\:{b}\:=\:−\mathrm{3} \\ $$$$ \\ $$
Commented by peter frank last updated on 08/Feb/20
$${thank}\:{you} \\ $$
Commented by jagoll last updated on 08/Feb/20
$${with}\:{plesure} \\ $$